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Biology High School

Which of the following statements best proves that the law of conservation of mass is obeyed during photosynthesis? A: The starting total number of oxygen atoms in carbon dioxide is equal to the ending total number of oxygen atoms in glucose. B: The starting total number of oxygen atoms in carbon dioxide gas is equal to the ending total number of oxygen atoms in glucose and oxygen. C: The total mass of glucose and oxygen formed from photosynthesis is equal to the total mass of carbon dioxide and water used up during the reaction. D: The total mass of glucose and carbon dioxide formed from photosynthesis is equal to the total mass of oxygen and water used up during the reaction.

2 months ago

Solution 1

Guest #10486

2 months ago

Answer: C: The total mass of glucose and oxygen formed from photosynthesis is equal to the total mass of carbon dioxide and water used up during the reaction.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Photosynthesis is a phenomenon in which green plants containing chlorophyll use sunlight as a source of energy to convert carbon dioxide and water to form glucose and oxygen.

$6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2$

Solution 2

Guest #10487

2 months ago

D hope you enjoy :D .....................................

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Correct answer: C). Fungicides interfere with fungal growth and reproduction, while genetic engineering produces plants resistant to fungi.

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In heterosporous plants microgametophytes produce sperm.

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Heterosporous refers to the plants producing different types of spores that are different in structure, size and function.

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In leghorn chickens colored feathers are produced by a dominant allele, c. white feathers are produced by the recessive allele, c. the dominant allele, i, of another independent gene inhibits expression of color in birds with genotypes cc or cc, giving them a white phenotype as well. a colored rooster is mated with a white hen and produces many offspring, all colored. give the genotypes of both parents and the offspring.

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When a male also has CC, the female will still have cc, but neither will I. The important thing to note is that all of the eggs are colored, and the further discussion can be defined as follows:

To also be colored, the male must have at least one C and cannot have the dominant I. This hen has a cc and/or an I to show that she is not colored.
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Nevertheless, for all the chicks to be colored, the female hen must not possess any inhibitor alleles (otherwise around 50% would be white for that reason alone).
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Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.

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That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.

However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).

So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).

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